I am trying to convert a test result that is provided as mg/L to ppm. The specification requirement is 600 ppm (parts per million) and my test result is shown as 711 mg/L. If remember correctly the conversion is equivalent but I am not sure.
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Re: mg/L to ppm
Many resources you find show mg/L the same as ppm, but its not exactly true.
Pure water at standard temperature and pressure has a density of 1 kg/L, therefore:
mg/L = mg/kg = ppm
But that is only true when using pure water at standard temperature and pressure. Any other substance will have a different density and will not be a direct conversion between mg/L and ppm.

Re: mg/L to ppm
Hi, for a solidsolid system, the conversion for ppm is mg/kg. For a solidliquid system, the conversion is mg/L. For a gasgas system, the conversion is uL/L.
In a solidliquid system you can calculate proportions easily, using dilution factors etc. As the liquid is effectively just a carrier, the density of the liquid is not usually important.
In your system, 711mg/L is 711ppm, if it was measured at room temperature, or at some other specified temperature of interest.
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Re: mg/L to ppm
i have a small conversion to make can you help to sort it out.
i am adding 80 grams of color in one litre water and out of this i am using 50 ml to 40 kg mass
i am adding 60 grams of color in 600 ml of water and out of this i aming using 4 ml to 40 kg same mass mentioned above.
can you calculate and tell the total ppm of color in this 40 kg mass
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Re: mg/L to ppm
Originally posted by Unregisteredi have a small conversion to make can you help to sort it out.
i am adding 80 grams of color in one litre water and out of this i am using 50 ml to 40 kg mass
i am adding 60 grams of color in 600 ml of water and out of this i aming using 4 ml to 40 kg same mass mentioned above.
can you calculate and tell the total ppm of color in this 40 kg mass
For your first one, you are taking 50mL/1000mL x 80g. = weight A.
Weight A x1000 = mg of weight A.
this weight A (in mg) is going in to 40kg.
Now work out how many mg of A is in each kg. That is your answer. (mg/kg = ppm)
Have a go at the second one yourself. You are welcome to post back here if you would like your answers checked. Good luck with your studies.
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Re: mg/L to ppm
Hai there im sorry but i am confused with your reply please see if i got it right
I take 20 ml from a solution of 2.19g/100 ml so inorder to convert it to ppm 0r mg/kg
it would be 20ml/(100ml*2.19gm) = 91.324 mg
please do help me out as i cant find the answers to this any were else !
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Re: mg/L to ppm
Originally posted by fuzik View PostHai there im sorry but i am confused with your reply please see if i got it right
I take 20 ml from a solution of 2.19g/100 ml so inorder to convert it to ppm 0r mg/kg
it would be 20ml/(100ml*2.19gm) = 91.324 mg
please do help me out as i cant find the answers to this any were else !
In 100mL you have 2.19g, in 20mL you have 20/100 of that.
2.19g x (20/100) = 0.438g, or 438mg
These are proportion calculations, so always work out what proportion you are taking.  In this case a fifth. Hope this helps, and good luck with your studies.
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Re: mg/L to ppm
Okay i am sorry to bother you again its jut my supervisor is on a holiday
If i took .005 litres (5 mL) from a standard solution of 21900mg/1litre
Here 21900mg/1litre = 21900 ppm
but if i take out .005 ml from this i have 109.5 mg in it
is 109.5mg/.005ml also = 109.5 ppm? I would really appreciate it , thank you!
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Re: mg/L to ppm
Originally posted by Unregistered View PostOkay i am sorry to bother you again its jut my supervisor is on a holiday
If i took .005 litres (5 mL) from a standard solution of 21900mg/1litre
Here 21900mg/1litre = 21900 ppm
but if i take out .005 ml from this i have 109.5 mg in it
is 109.5mg/.005ml also = 109.5 ppm? I would really appreciate it , thank you!
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Re: mg/L to ppm
I am trying to test the salinity of soils for state regulations, post oil/produced water spills. New 2010 regulations restrict our former testing method
Typically we run into chloride concentrations of 1020k mg/kg. We look for "clean" material with lab results of <200 mg/kg
I have a new probe I want to field test to get preliminary results.
Can I measure out a certain amount of soil (X grams) and certain amount of distilled water (X liters) and get a useable result?
Thank you
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Re: mg/L to ppm
suppose the Cl =0.14mg/l after analysis with ion chromotography, can I say again Cl = 0.14ppm?
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Re: mg/L to ppm
I am trying to convert a test result that is provided as mg/L to ppm.
The specification requirement is 2000 ppm (parts per million) and my test result is shown as 708 mg/L.
If remember correctly the conversion is equivalent but I am not sure.[/QUOTE]
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