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ug/ul to uM

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  • ug/ul to uM

    I need help with this conversion. I have an oligo that is 0.1ug/ul (20ul total). From this I need to make a 1uM stock to use in a PCR rxn......

  • #2
    Re: ug/ul to uM

    Originally posted by Unregistered
    I need help with this conversion. I have an oligo that is 0.1ug/ul (20ul total). From this I need to make a 1uM stock to use in a PCR rxn......
    What is the weight of 1mol? - This would be the amount you need in 1L. From that, you can work out how much you need in the volume you need to make up.

    If this is typically the sort of work you are involved in, is there a course you can do that will help you come to grips with these dilution problems? - While we converters are always happy to help, it is always MUCH better to work them out yourself than ask unknown cyberspace people.

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    • #3
      Re: ug/ul to uM

      I'm not sure I understand what you mean by the weight of the 1uM? The oligo is 329 pmoles total. I haven't been able to find a class, but I have been looking for books that could help with this sort of thing, because I do spend quit a bit of time doing dilutions....

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      • #4
        Re: ug/ul to uM

        Originally posted by Unregistered
        I'm not sure I understand what you mean by the weight of the 1uM? The oligo is 329 pmoles total. I haven't been able to find a class, but I have been looking for books that could help with this sort of thing, because I do spend quit a bit of time doing dilutions....
        You need to know the molecular weight of your sample. I'm not sure what an oligo is, but if you provide that information, I can help you.

        1M means a solution that has a concentration of 1 mol per liter.

        There are 1,000,000 mols in 1 mol.

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        • #5
          Re: ug/ul to uM

          An oligo is just a short sequence of nucleotides. The molecular weight is 6094.

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          • #6
            Re: ug/ul to uM

            Originally posted by Unregistered
            An oligo is just a short sequence of nucleotides. The molecular weight is 6094.
            In a 1M solution, you would have 6094g/L (not possible, I know)

            in a 1M solution, you would have 6094g/L (0.006094g/L)

            Not sure how much stock solution you want to make up, but for example, 250L would require 0.006094 x 250 = 1.5235g.

            The volume of your original solution that contains 1.5235g is 1.5235 0.1 = 15.235L

            To make 250L of 1M solution, you use 15.235L of solution, and 234.765L of solvent.

            If you want to use all your original solution, the total volume is
            20 x 0.1 0.006094 = 328.2L, so add 308.2L to your original volume.

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            • #7
              Re: ug/ul to uM

              thank you for your help.....

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              • #8
                Re: ug/ul to uM

                HI THERE,

                Iam a tad confused with my lab manual instructions, they are asking me to add 400 ug proteinase K to my lysed cells- Calculate what volume of proteinase K at a stock solution of 20 mg/Ml will give me 400 ug. and they have only provided 30 ul of proteinase K...so how do I calculate the volume of proteinase K to calculate.. Thanks you for your help.
                Last edited by JohnS; 05-11-2011, 07:54 AM.

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                • #9
                  Re: ug/ul to uM

                  Originally posted by Unregistered View Post
                  HI THERE,

                  Iam a tad confused with my lab manual instructions, they are asking me to add 400 ug proteinase K to my lysed cells- Calculate what volume of proteinase K at a stock solution of 20 mg/Ml will give me 400 ug. and they have only provided 30 ul of proteinase K...so how do I calculate the volume of proteinase K to calculate.. Thanks you for your help.
                  400 g is 0.4 mg
                  Your stock is 20 mg/mL so
                  0.4 mg x 1 mL/20 mg = .020 mL = 20 L

                  Perhaps easier to visualize, 20 mg/mL = 20 g/L
                  You need 400 g, dividing by 20, you need 20 L.

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