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20-hydroxyecdysone

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  • JohnS
    replied
    Originally posted by azammikani View Post
    I need to calculate the concentration of an injected chemical (20-hydroxyecdysone or 20E) in terms of ng/ml and μg/ml given that the concentration range used is 0.01, 0.05, 0.1, 0.25, 0.5, 1.0, 2.0 and 2.5 mM and the injected volume is 10 microliters.

    20E molar mass: 480.63 g/mol

    another way: 10
    μl of 20E was injected into an insect after being dissolved in 10% ethanol and diluted so that the final concentration of EtOH was less than 0.1% and those of 20E were 0, 0.01, 0.05, 0.1, 0.25, 0.5, 1.0, 2.0 and 2.5 mM
    Concentration or amount?
    M is the symbol for molarity, a concentration in moles per liter (mol/L). A 1 M solution is one mole (or one molar mass) per liter, so 480.63 g/L for this substance. Let me work the 1 mM example for you and you can do the others by substitution.

    If 1 M solution is 480.63 g/L, then 1 mM is 480.63 mg/L, or 480.63 g/mL or 480.63 ng/L
    If you administer 10 L, that is a total amount of 4806.3 ng or 4.8063 g

    For your other concentrations, just multiply above by 0.01, 0.05, . . . 2.5

    Leave a comment:


  • azammikani
    started a topic 20-hydroxyecdysone

    20-hydroxyecdysone


    I need to calculate the concentration of an injected chemical (20-hydroxyecdysone or 20E) in terms of ng/ml and μg/ml given that the concentration range used is 0.01, 0.05, 0.1, 0.25, 0.5, 1.0, 2.0 and 2.5 mM and the injected volume is 10 microliters.

    20E molar mass: 480.63 g/mol

    another way: 10
    μl of 20E was injected into an insect after being dissolved in 10% ethanol and diluted so that the final concentration of EtOH was less than 0.1% and those of 20E were 0, 0.01, 0.05, 0.1, 0.25, 0.5, 1.0, 2.0 and 2.5 mM
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