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ng/ml to pmol/g

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  • ng/ml to pmol/g

    Hello to everyone,

    I have some difficulties in converting from ng/ml to pmol/g. I have a concentration of 3.50 ng/ml of total T3 (triiodothyronine, mw= 651) found in a suspension derived from an homogeneted mouse liver (weight=100mg). Considering that the suspension total volume is 100ul, in order to find the concentration in my suspension volume I divide 3,50/10, so obtaining 0,350 ng/100ul of suspension. Then I want to convert ng/100ul to ng/g and, in order to do so, I divide 0,350 ng/ml for the weight of my tissue (100mg in this case, or 0,1 g). So, from 0,350/0,1, I obtain 3,5 ng/g. Then I want to convert this concentration to pmol/g and, in order to do so, I moltiplicate 3,5 ng/g * (1mol/651 g) to obtain 0,00537 nmol/g. Eventually, I moltiplicate 0,00537*1000 to obtain 5,37 pmol/g. Is my reasoning right? Thank you very much in advance!

    Andrea
    Last edited by andreaberto; 03-12-2021, 03:14 PM.

  • #2
    Originally posted by andreaberto View Post
    Hello to everyone,

    I have some difficulties in converting from ng/ml to pmol/g. I have a concentration of 3.50 ng/ml of total T3 (triiodothyronine, mw= 651) found in a suspension derived from an homogeneted mouse liver (weight=100mg). Considering that the suspension total volume is 100ul, in order to find the concentration in my suspension volume I divide 3,50/10, so obtaining 0,350 ng/100ul of suspension. Then I want to convert ng/100ul to ng/g and, in order to do so, I divide 0,350 ng/ml for the weight of my tissue (100mg in this case, or 0,1 g). So, from 0,350/0,1, I obtain 3,5 ng/g. Then I want to convert this concentration to pmol/g and, in order to do so, I moltiplicate 3,5 ng/g * (1mol/651 g) to obtain 0,00537 nmol/g. Eventually, I moltiplicate 0,00537*1000 to obtain 5,37 pmol/g. Is my reasoning right? Thank you very much in advance!

    Andrea
    The conversion to picomoles is correct. Is the density of homogeneted mouse liver 1 g/mL? That is does 1 mL also weigh 1 g. If so your conversion is correct. (I am assuming it is as you say you have 0.1 mL of suspension and it weighs 100 mg.

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    • #3
      Thank you so much!

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