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lb/1000 lbs of gas

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  • lb/1000 lbs of gas

    Off the wall question, but looking for extra input or insight into my insanity here.
    I have two routes in which I would approach this issue:
    1) Calculate based on a sampled volume
    2) Calculate based on rates

    With approach 1, it would use this equation:
    With approach 2, I have two equations to use, either based on the rate of ACFM or the rate as DSCFM, and these numbers calculate out fairly similarly IMHO:
    In both instances here, I will correct these from lb/hr to klbs/hr, and I will take the calculated emission rate of lb/hr divided by this klbs/hr

    For all of the above references also:
    Mn(grams) = Weight of Sample, 140.4 mg or 0.1404 g
    Vmstd = Volume Sampled - corrected to standard conditions, 57.076 dscf
    2.595*10-3 is n/V = P/RT from the ideal gas law
    Md = Molecular weight - dry, 29.30 lb/lb-mole, or Tg/Tg-mole, or whatevers
    Vlc = Volume of Condensate collected in sample, 676.8 grams
    2.205*10-3 assumes 1 ml of water = 1 gram
    PPSI = Pressure of gas stream, 14.45 PSI
    Qa = Actual Volume Flow Rate of gas stream, 55,437 acfm
    Bw = Moisture content of gas stream, 35.86%
    R = Universal Gas Flow Constant, 1545 ft/lbf
    Mw/Ms = Molecular weight - wet, 25.25 lb/lb-mole
    Ts = Temperature of gas stream as Rankine, 1014 R
    Qstd = Dry Volume Flow Rate of gas stream, 18,197 dscfm
    Elb/hr = Emission Rate as Pounds per Hour, 5.92 lb/hr
    When I play with these equations though, I get different numbers. Using the first approach, I calculate 1.4 lb/klbs. Using the second approach, while both equations calculate out similarly I will use just the first equation, it calculates out 0.0827 lb/klbs. So entirely different numbers.

    I will just leave this here for whoever wants to tell me where all I am being stupid at.