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Gas KG/hr to Nm3/hr

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  • rubelahamed
    replied
    Hi All,

    I have been stumped on how to convert this mixture of gases from kg/hr to nm3/h assuming 1 atmosphere and 0oC the gas mixture is as follows Hydrogen 35%, Carbon Dioxide 20.8%, Carbon Monoxide 11.68%, Methane 16.28%, ethane 1.34%, Ethene 3.11% Nitrogen 10.2%.Since all conversions were 1:1 I was able to convert 1:1 g/L into kg/m and am using these conversions for my table math.​

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  • gubment_cheez
    replied
    I reached a value of 325.7491405
    I pulled the density value in g/L from Wikipedia's Physical Property panel of each gas at 0C. For values that were not available on wikipedia I searched bing for gas density at 0c and took the first value available. If this was not in g/L I converted it to g/L using the conversion tools provided by onlineconversion.com. All conversions were 1:1 (i.e. kg/m to g/L).
    Since all conversions were 1:1 I was able to convert 1:1 g/L into kg/m and am using these conversions for my table math.

    Additionally I was also able to observe the error in the percentage of the mixture, and I believe it is either a typo, or some particulate matter in the gas production. I extrapolated about 4.9714 kg/m other material based on the unidentified percentage and volume percentage​ remaining after the other gasses were accounted for.
    kg/m % kg/m % Total mass
    per hour
    Hydrogen 0.179 35 0.0627 20.408
    Co2 1.977 20.80 0.4112 133.953
    Co 1.25 11.68 0.1460 47.559
    Methane 0.717 16.28 0.1167 38.024
    Ethane 1.3562 1.34 0.0182 5.920
    Ethylene (Ethene) 1.242 3.11 0.0386 12.582
    Nitrogen 1.2506 10.20 0.1276 41.553
    Subtotal 300 kg
    Total 98.41 0.921% 325.75 m
    Other/Unlisted 1.59 0.079%

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  • JohnS
    replied
    You need to determine the average molar mass of the mixture. Your constituents only add to 98.41% of the mixture, so something is missing or there is a typo. For each gas determine its molar mass (I cheated and used integer atomic mass units.)Compute the weighted average. For what is identified i get 20.2 g/mol (or kg/kmol). A mole of ideal gas at "normal" conditions occupies 22.414 L/mol (or m/kmol).

    300 kg x 1 kmol/20.2 kg x 22.4 m = 333 m

    My numbers are all rounded and approximate, because some constituents are missing, and I used rounded atomic masses.

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  • gubment_cheez
    replied
    Hello Chris, what calculations did you use to come up with your 1459 nm3/h value?

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  • chris102030
    started a topic Gas KG/hr to Nm3/hr

    Gas KG/hr to Nm3/hr

    Hi All,

    I have been stumped on how to convert this mixture of gases from kg/hr to nm3/h assuming 1 atmosphere and 0oC the gas mixture is as follows Hydrogen 35%, Carbon Dioxide 20.8%, Carbon Monoxide 11.68%, Methane 16.28%, ethane 1.34%, Ethene 3.11% Nitrogen 10.2%. The total weight of the gas being produced is 300kg/hr by my calculations this will equate to 1459 nm3/h is anyone able to assit me with this? I only have a basic background in chemistry
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